Ok ,, So I looked on the hognose Morph calculator but I can't figure out how to enter a poss het into the equation .. Here goes , I bred an anaconda het albino to a het albino that was 66% poss het for axanthic ... So the babies should be a low percentage het axanthic yes ??? .. does any body know the figure off hand ???

I'm not looking to add value with the low poss het axanthic part just wanted to know for my own data ,, the babies produce are actuallu 66% het albino since both parents where hets

This is the only chart I've ever found that does that type if calculation. Still have not figured out the math behind it, but according to them, they drop to 33% het axanthic.

My limited understanding is that whatever % het the parents are you just add up, and divide by 2. So one parent is 66% chance and the other is 0%, 66 + 0 = 66. Then 66 divided by 2 = 33%. Since genes are in pairs and the parent only passes one half of the pair, that is where the divide by 2 part comes in.

And I know that formula doesn't work on 100% hets, but I think that is because you should produce a visual and have to subtract that from the equation. 100% + 100% = 200 / 2 should = 100. I mean, technically they did pass the gene on 100% of the time by statistics, but just one snake lucked out and got the 2 copies, 2 got one copy, and 1 snake got none.

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