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Q: Possible het percentages ??
Posted By:

Doomtrooper

In Relation To:

HOD 18-02 [HOD 18-02]

Ok ,,   So I looked on the  hognose Morph calculator  but I can't figure out how to enter a poss het  into the equation ..  Here goes , I bred an anaconda  het albino  to a het albino  that was 66%  poss het for axanthic  ... So the babies should be a low percentage  het axanthic yes ???    ..  does any body know the figure  off hand ???


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Points: 250
Topics: Genetics
Species: Other Colubrids > Other Colubrids > Heterodon nasicus
Administrative: Show/Hide

Member Comment 8/28/2018 9:09:01 AM

Sonja K. Reptiles

If it were a proven het for Axanthic, then the babies would be possible 50% hets. 

If I was making an ad, I'd say parents were an Anaconda Het Albino to an Albino  66% het Axanthic (unproven).

The babies produced were Albino Anacondas, Anacondas 100% Het Albino, Albinos, and 100% Het Albinos. All could possibly be 50% het for Axanthic, too.

 
Author Comment 8/28/2018 3:57:05 PM

Doomtrooper

I'm not looking to  add value  with the low poss het axanthic part  just wanted to know for my own  data ,,   the babies produce are actuallu 66%  het albino  since both parents  where hets

 
Member Comment 8/28/2018 4:04:59 PM

Sonja K. Reptiles

Whoops! I skipped over a het. EmbarassedYell

 
Member Comment 8/29/2018 11:00:14 AM

Cenobite

Math sucks!

 
Member Comment 8/29/2018 11:02:58 AM

Sonja K. Reptiles

Lol... I'd go with 25% het axanthic.

 
Accepted Answer 9/6/2018 7:16:40 AM

indyana

This is the only chart I've ever found that does that type if calculation. Still have not figured out the math behind it, but according to them, they drop to 33% het axanthic.

http://www.glidernursery.com/percent-het-chart.html

 
Assisted Answer 9/12/2018 7:09:24 PM

Jeanie Owens

33% is right on. 

My limited understanding is that whatever % het the parents are you just add up, and divide by 2.  So one parent is 66% chance and the other is 0%, 66 + 0 = 66.  Then 66 divided by 2 = 33%.  Since genes are in pairs and the parent only passes one half of the pair, that is where the divide by 2 part comes in. 

And I know that formula doesn't work on 100% hets, but I think that is because you should produce a visual and have to subtract that from the equation.  100% + 100% = 200 / 2 should = 100.  I mean, technically they did pass the gene on 100% of the time by statistics, but just one snake lucked out and got the 2 copies, 2 got one copy, and 1 snake got none.  

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